Question #153224

Determine the smallest size of hole that can be punched in 12 mm thick MSÂ

plate having ultimate shear stress of 390 N/mm2 , if permissible crushingÂ

stress for the punch material is 2.4 kN/mm2.

Expert's answer

Ultimate shear stress=\tau_u= 390 N/mm^{2}, thickness= 12mm,

Permissible crushing stress=2.4 kN/mm^{2}

Axial shear force= (\frac{\pi d^2}{4})\tau= F ,In case of crushing

F=\pi dt \times \sigma_c as we know that in case of small size both force will be same

\pi dt \sigma_c=\frac{\pi d^2}{4}\times \tau_u

12 \times 2400= \frac{d}{4}\times 390

d=295.38 mm

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